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K324 / 2027
Qualitative Analysis

Lesson 1 of 4

Distinguish aqueous cations

Observe a few drops first, then add the reagent in excess.

O-Level 6092 (2026) / SEC G3 K324 (2027)

  • I can identify aqueous cations.Syllabus

    Syllabus K324, 6(a). Identify aqueous cations

Distinguish aqueous cations

Observe a few drops first, then add the reagent in excess.

Make a guess. You are not marked.

Aqueous sodium hydroxide is added to a solution of iron(II) ions and a green precipitate forms. The tube is left open to the air. What happens to the precipitate?

  1. It turns red-brown on standing, as air oxidises it
  2. It stays green, as the precipitate is already formed
  3. It dissolves to a colourless solution over time
Show the answer

It turns red-brown on standing, as air oxidises it

Oxygen in the air oxidises iron(II) hydroxide to iron(III) hydroxide, which is red-brown. Mark schemes reward this observation.

Use a fresh small portion of the unknown for each reagent. Add aqueous sodium hydroxide or aqueous ammonia a little at a time, mix, and record any precipitate. Then add excess reagent and record whether that precipitate dissolves. A precipitate is an insoluble solid, not simply a coloured solution.

Cation observations
CationAqueous NaOHAqueous ammonia
Al3+White precipitate; dissolves in excess to a colourless solutionWhite precipitate; insoluble in excess
Ca2+White precipitate; insoluble in excessNo precipitate
Cu2+Light blue precipitate; insoluble in excessLight blue precipitate; dissolves in excess to a dark blue solution
Fe2+Green precipitate; insoluble in excess; turns red-brown on standingGreen precipitate; insoluble in excess; turns red-brown on standing
Fe3+Red-brown precipitate; insoluble in excessRed-brown precipitate; insoluble in excess
Zn2+White precipitate; dissolves in excess to a colourless solutionWhite precipitate; dissolves in excess to a colourless solution
NH4+On warming, ammonia evolves; test with damp red litmusNot a useful ammonium test: the reagent already contains ammonia

Most precipitates in this table are metal hydroxides. For example, Cu2+(aq) + 2OH-(aq) -> Cu(OH)2(s). The copper ion can give a clear blue solution before reaction and a cloudy light-blue precipitate afterwards; describe both colour and physical change. Complex-ion formulae for reactions with excess ammonia are not required.

Worked exampleDistinguish aluminium from zinc

An unknown forms a white precipitate soluble in excess NaOH. What next?

Try it first. Then show the worked stepsHide the worked steps
  1. This result fits both Al3+ and Zn2+; it is not enough to identify either.
  2. Test a fresh portion with aqueous ammonia, then excess.
  3. A white precipitate remaining in excess supports aluminium; dissolution to a colourless solution supports zinc.
Answer

Use a second discriminating test, rather than repeating the same ambiguous observation.

Check your understanding

With aqueous ammonia, an unknown gives a light-blue precipitate that dissolves in excess to a dark-blue solution. Which cation is likely present?

  1. Zn2+, since its precipitate also dissolves in excess aqueous ammonia
  2. Fe2+, whose green precipitate looks blue at first in excess ammonia
  3. Cu2+, which gives both the blue precipitate and the dark-blue solution
Show the answer

Cu2+, which gives both the blue precipitate and the dark-blue solution

Copper(II) hydroxide is a light-blue precipitate, and it dissolves in excess ammonia to give a dark-blue solution. Record both stages as evidence.

Exam-style question

Aqueous ammonia is added a little at a time, until in excess, to a solution containing copper(II) ions. Describe what you would observe. [2]

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Sort these

Aqueous sodium hydroxide is added to each cation until it is in excess. Sort the cations by what you see.

Show the answer

Precipitate dissolves in excess: Al3+ / Zn2+

Precipitate stays in excess: Ca2+ / Fe3+ / Cu2+ / Fe2+

No precipitate; ammonia given off on warming: NH4+