9478 / 2027
Oscillations overview

Chapter revision

Revision summary

Key ideas, equations and common mistakes. Open any topic below for the full explanation.

State equilibrium, displacement sign, amplitude and the chosen time origin. Then check whether the motion is ideal free SHM, damped, or maintained by a periodic drive.

Describe a complete cycle

T = 1/f = 2π/ω
ω = 2πf

Amplitude x0 is maximum |x|, not the extreme-to-extreme distance. A full cycle returns to the same state of motion; opposite-direction centre crossings are half a period apart. Frequency counts cycles per second, while angular frequency gives phase advance in rad/s.

Phase identifies the stage of a cycle. For same-frequency traces, a positive time separation Δt between corresponding stages gives phase-difference magnitude 2πΔt/T. Name the leading trace. A quarter-cycle difference is π/2; a half-cycle difference is π. Equal displacement alone does not identify equal phase.

For measurements, calibrate position and timing, mark equilibrium, track one point and time repeated complete cycles. Check rate/amplitude changes and keep the release and apparatus conditions controlled. Repeats do not remove a wrong reference, miscount or perspective error.

Use the restoring condition

a = -ω2x
x = x0 sin(ωt)

SHM needs both proportionality to displacement and acceleration towards equilibrium. Its a-x graph is a straight line through the origin with negative gradient -ω2. The sine solution shown chooses t = 0 at a positive-direction centre crossing; a release at the positive extreme needs a different phase.

Select velocity sign and match graph times

v = v0 cos(ωt), with v0 = ωx0
v = ±ω√(x02 - x2)

Choose the square-root sign from the direction of motion. At equilibrium speed is greatest and restoring acceleration is zero. At either extreme velocity is zero and acceleration is greatest in magnitude towards equilibrium. Velocity leads sine displacement by π/2; acceleration and displacement are in antiphase.

Velocity is the x-t gradient and acceleration the v-t gradient. For sampled positions, Δx/Δt gives interval averages, approximately associated with their midpoints. Pair acceleration estimates with displacement at corresponding times. Use actual calibrated records on both sides of equilibrium to investigate a-x proportionality; generated model data are not independent confirmation.

Smaller intervals reduce a finite-gradient approximation error only while position and timing resolution remain adequate. Differencing amplifies noise. Distinguish approximate interval results from exact instantaneous model values.

Keep the energy account and reference clear

For the horizontal linear spring model:
Ep = ½kx2,   Ek = ½mv2
Etotal = ½mω2x02

With no losses or drive, total mechanical energy is constant. In the equilibrium-zero reference, it is all kinetic at the centre and all elastic potential at either extreme. Both stores are present between them. Gravitational energy is unchanged for the horizontal model; a vertical model must include its gravitational contribution.

For unchanged mass and linear stiffness, doubling amplitude doubles maximum speed and acceleration magnitude, quadruples energy and leaves period unchanged within the model. Energy repeats every T/2, although the full signed motion repeats after T.

Compare like initial conditions

For the same mass, stiffness, initial displacement and release from rest: light/underdamping gives decreasing oscillations; critical damping gives the fastest nonoscillatory return; heavy/overdamping returns more slowly. These statements refer to the stated comparison, not every possible initial velocity.

Damping transfers mechanical energy to other forms. Car suspension damping limits repeated bouncing, with rapid settling as a design aim. More damping is not always better.

Read the response axes and drive conditions

Natural frequency describes free oscillation; the external driver sets driving frequency. After transients settle, a linear forced response repeats at that driving frequency. Steady amplitude with damping requires continuing energy input to replace losses.

An amplitude-versus-driving-frequency graph peaks at resonance, close to or at the natural frequency under the relevant conditions. At the same drive strength, greater damping lowers and broadens the displacement-response peak; its position need not be exactly the undamped natural frequency.

Resonance can help build a swing's motion or a musical resonator's response, but can cause unwanted machine-support vibration. Identify the driver, responding system and energy transfer. Control the driving-force amplitude when comparing the supplied response curves.

Oscillation quantities, signs and units
QuantitySymbolUnit or meaning
Displacement; amplitudex; x0m; x signed, x0 non-negative
Period; frequencyT; fs; Hz
Angular frequencyωrad/s
Phase; phase differenceφ; Δφrad, or an explicitly converted angle
Velocity; maximum speedv; v0m/s
Accelerationam/s2
Mass; restoring stiffnessm; kkg; N/m
ForceFN
Kinetic; potential energyEk; EpJ; 1 mJ = 0.001 J

The phase angle φ here is not gravitational potential: the named quantity and its units distinguish those uses. Keep radians in ωt when ω is in rad/s.

Back to describing an oscillation

Practise exam questions

Write your answer first, then tick the mark points it makes.

Exam-style question

Define simple harmonic motion. [2]

Saved on this browser only. Anyone using this browser can see it.

Exam-style question

A mass on a spring oscillates with simple harmonic motion of amplitude 0.040 m and period 0.50 s. Calculate its maximum speed, and its speed when its displacement is 0.020 m. [4]

Saved on this browser only. Anyone using this browser can see it.

Exam-style question

A displacement-time graph of a body in simple harmonic motion is a sine curve with peaks at +3.0 cm and -3.0 cm. One complete cycle takes 0.40 s. Use the graph to find the maximum acceleration of the body. [3]

Saved on this browser only. Anyone using this browser can see it.

Exam-style question

A lightly damped oscillator is driven by a periodic force whose frequency is slowly increased. Explain why the amplitude becomes very large at one frequency, and state the effect of increasing the damping. [3]

Saved on this browser only. Anyone using this browser can see it.

Exam-style question

Data-based question: A footbridge that sways [20]

Some footbridges sway sideways when crowded. When we walk, each foot pushes slightly sideways, first one way and then the other, so the sideways push repeats once every two steps. At about 2 steps per second this is about 1 Hz. Engineers model the sideways motion of one footbridge as a mass-spring oscillator with an effective mass of 1.2 x 105 kg and a natural frequency of 1.0 Hz. They push the bridge sideways once and record the amplitude after each complete cycle, first without and then with dampers fitted.

Table 1. Amplitude after each cycle of free oscillation
cycle012345
no dampers / mm20.018.016.214.613.111.8
with dampers / mm20.010.05.02.51.30.6

A crowd crossing the bridge puts about 60 J of energy into the sideways oscillation in each cycle. Walkers feel unsafe if the maximum sideways acceleration is more than 0.20 m s-2.

  1. (a) Define simple harmonic motion. [2]
  2. (b) Calculate the effective stiffness k of the bridge. [2]
  3. (c) For the 20.0 mm oscillation, calculate the maximum speed and the maximum acceleration of the bridge. [2]
  4. (d) Calculate the energy of the oscillation when the amplitude is 20.0 mm. [2]
  5. (e) Use Table 1 to show that, without dampers, the amplitude falls by the same fraction each cycle, and calculate the fraction of the energy lost per cycle. [3]
  6. (f) Explain why a crowd walking at about 2 steps per second can make the bridge sway strongly. [3]
  7. (g) The amplitude stops growing when the energy lost per cycle equals the energy put in per cycle. Use this idea to evaluate whether the dampers make the bridge comfortable for this crowd. [5]
  8. (h) State one assumption in the model used in (g). [1]

Saved on this browser only. Anyone using this browser can see it.

Quick recall

Card 1 of 6. Answer in your head, then check.

An oscillator crosses equilibrium moving right, then crosses it moving left 0.785 s later. What is its period?

Review a topic

Read whole chapter

Next chapter: Wave Motion