Chapter revision
Revision summary
Key ideas, equations and common mistakes. Open any topic below for the full explanation.
Identify the nodes, the component and the stated conditions. Then choose a relationship that uses the correct current, voltage and source model.
Connections and measurements
- Series components share current along an unbranched path; parallel components share both endpoints and therefore p.d.
- An ammeter measures current in its own path. A voltmeter measures p.d. between its own terminals. Pair component V with component I before using R = V/I.
- Check range, resolution, zero, polarity, loading and thermal conditions. Repeated readings assess scatter but do not remove a consistent wrong-endpoint or zero error.
Resistance and material behaviour
A = πd2/4
Rseries = R1 + R2 + …
1/Rparallel = 1/R1 + 1/R2 + …
Convert diameter before squaring it. At fixed material, temperature and length, resistance is proportional to 1/A; doubling diameter quarters resistance. On an I-against-V plot, only a straight line through the origin has gradient 1/R at all points.
- Ohmic resistor: proportional I and V under fixed physical conditions.
- Filament lamp: settled heating raises resistance, so the I-V curve becomes less steep at greater voltage magnitude.
- Semiconductor diode: forward conduction and small reverse current before breakdown; no universal forward threshold.
- NTC thermistor: warming lowers resistance. A self-heated voltage sweep differs from a fixed-temperature, low-field measurement.
For a typical metal at the same electric field, greater scattering lowers mean drift speed while carrier density changes little. For the stated NTC regime, increased carrier number density is the main explanation for falling resistivity. Random thermal motion is not the directed drift.
Sources, networks and outputs
I = Es/(Rexternal + r)
Pload = IVterminal
Pinternal = I2r
EsI = Pload + Pinternal
These source signs describe current delivered to the load. A terminal-V-against-I line has intercept Es and gradient -r. Maximum load power occurs at Rexternal = r for this fixed source model, where load and internal powers are equal; this is not maximum efficiency.
Reduce a network to find total current, then work back to its branch voltages and currents. After a connection changes, recalculate the complete network: another branch's voltage may change even if its resistance does not.
Vout = VsRlower/(Rupper + Rlower)
Use the actual supply-terminal p.d. The selected output determines the numerator. Work through sensor resistance, total current and output rather than memorising a direction. An output load is parallel with its selected arm and changes the effective divider.
Quantity and unit reference
| Quantity | Symbol | SI unit |
|---|---|---|
| Current | I | A |
| Potential difference | V | V = J/C |
| Source e.m.f. | Es, E | V |
| Resistance; internal resistance | R; r | Ω = V/A |
| Resistivity | ρ | Ω m |
| Length; diameter | l; d | m |
| Cross-sectional area | A | m2 |
| Power | P | W = J/s |
| Charge | Q | C = A s |
| Time | t | s |
Read symbols in context: A as area differs from A as the ampere unit, and C as charge's unit differs from a node labelled C. Useful prefixes are micro (µ, 10-6), milli (m, 10-3), kilo (k, 103) and mega (M, 106). Squared lengths and areas require squared conversion factors.
For a calculation, draw or trace the nodes, choose reference directions and endpoints, state the component conditions, solve with units, then check current and energy accounts. For a measurement, retain the actual readings and instrument information as well as the inferred result.
Practise exam questions
Write your answer first, then tick the mark points it makes.
Exam-style question
Define the resistivity of a material. [2]
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Exam-style question
A wire of length 2.0 m has a diameter of 0.50 mm. The resistivity of its material is 1.1 x 10-6 Ω m. Calculate its resistance. [3]
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Exam-style question
Explain why the terminal potential difference of a cell is less than its e.m.f. when it supplies a current. [2]
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Exam-style question
A student varies the current from a cell and plots terminal p.d. V against current I. The line is straight, meets the V-axis at 1.50 V and passes through (0.50 A, 1.10 V). Use the graph to find the e.m.f. and the internal resistance of the cell. [3]
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Exam-style question
Data-based question: A portable speaker battery pack [15]
A portable speaker runs from a rechargeable battery pack labelled "5000 mA h". A student connects the pack to a variable resistor and measures the terminal potential difference V for different currents I.
| I / A | 0.50 | 1.00 | 2.00 | 3.00 | 4.00 |
|---|---|---|---|---|---|
| V / V | 7.32 | 7.24 | 7.08 | 6.92 | 6.76 |
At normal volume the speaker draws 1.20 A. At full volume it draws 4.0 A.
- (a) Explain why the terminal p.d. falls as the current increases. [2]
- (b) Use the data to determine the e.m.f. E and the internal resistance r of the pack. [3]
- (c) Express the charge stored, 5000 mA h, in coulombs. [1]
- (d) Calculate how long the speaker can play at normal volume on a full charge. [1]
- (e) At normal volume, calculate the power delivered to the speaker, the power wasted in the pack, and the efficiency of the pack. [3]
- (f) The maker says the pack "is just as efficient at full volume". Use the data to evaluate this claim. [3]
- (g) The pack is recharged with a constant current of 2.0 A. Estimate the charging time and state one assumption you made. [2]
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Quick recall
R1 joins A to B, while R2 and R3 each join B to C. A source has external terminals A/C and a private internal node D before its internal resistance. Which redraw and terminal-voltage measurement preserve the intended circuit?
Review a topic
- Read connections and place meters
- Resistance, material and geometry
- I-V curves and temperature
- Sources with internal resistance
- Reduce a network and work back
- Potential dividers and sensors