Chapter revision
Revision summary
Key ideas, equations and common mistakes. Open any topic below for the full explanation.
- Moment of a force
- Moment = F x d. F in N; d is the perpendicular distance in m from the pivot to the force's line of action. Give N m and the clockwise or anticlockwise turning sense.
- Principle of moments
- For equilibrium, total clockwise moment = total anticlockwise moment about the same point. A stationary body also needs zero resultant force.
Before calculating a moment
- Name the pivot and extend the force's line of action.
- Choose the perpendicular distance to that line, not automatically the handle length.
- Convert distances to metres for a result in N m. Convert mass to force using W = mg when needed.
- A force whose line of action passes through the pivot has zero moment about it; the force may still be non-zero.
Build a balance equation
Include every force with a turning effect, including the object's own weight. Measure all lever arms from one common pivot and classify their turning senses. For a uniform metre rule, its weight acts at the 50 cm mark; a support elsewhere does not automatically remove that moment.
Centre of gravity and suspension
Represent the body's combined weight by one downward force at G. A uniform symmetrical object's G is at its geometric centre, but an irregular object needs evidence.
- Suspend the lamina freely and let it settle.
- Mark the vertical plumb-line position from that same suspension point.
- Repeat from another hole. The intersection of the two traces estimates G.
- Use a third suspension to check; thin, well-separated trace directions give a more useful intersection.
For a moments investigation, include hanger weights, keep forces vertical and measure from the actual pivot. For suspension, avoid clamping, parallax and a moving plumb line. Explain a specific limitation and its effect.
Pure: stability
About a possible toppling edge, the weight line determines whether weight gives a restoring or toppling moment. At the boundary it passes through the edge. With no sliding and otherwise comparable conditions, a lower G or a wider base in the tilt direction allows more tilt before toppling.
Back to moments and perpendicular distancePractise exam questions
Write your answer first, then tick the mark points it makes.
Exam-style question
A uniform plank of weight 200 N is balanced on a pivot at its centre. A child of weight 300 N sits 1.2 m to the left of the pivot. How far to the right of the pivot must an adult of weight 400 N sit so that the plank balances? [2]
Saved on this browser only. Anyone using this browser can see it.
Exam-style question
Define the moment of a force. A mechanic pushes at right angles on the end of a spanner 0.20 m from the centre of a nut with a force of 25 N. Calculate the moment of the force about the nut. [3]
Saved on this browser only. Anyone using this browser can see it.
Exam-style question
Describe how you would find the centre of gravity of a flat, irregularly shaped piece of card, using a pin, a stand and a plumb line. [3]
Saved on this browser only. Anyone using this browser can see it.
Exam-style question
Racing cars are built with a low centre of gravity and a wide wheel base. Explain why this makes them less likely to topple over when they are tilted. [3]
Saved on this browser only. Anyone using this browser can see it.
Quick recall
Viewed from the front, a 10 N force acts vertically downwards at a point to the right of a pivot. The handle is 0.50 m long, but the perpendicular distance from the pivot to the force's line of action is 0.30 m. What is the moment?