Lesson 1 of 3
Forces, mass and weight
I can distinguish contact and non-contact forces, including the specified examples.Syllabus
Syllabus K223 / K224, 3(a). Distinguish contact and non-contact forces, including the specified examples.
I can explain mass as a measure of the amount of matter in a body.Syllabus
Syllabus K223 / K224, 3(b). Explain mass as a measure of the amount of matter in a body.
I can describe a gravitational field as a region where a mass experiences gravitational attraction.Syllabus
Syllabus K223 / K224, 3(c). Describe a gravitational field as a region where a mass experiences gravitational attraction.
I can define gravitational field strength as gravitational force per unit mass.Syllabus
Syllabus K223 / K224, 3(d). Define gravitational field strength as gravitational force per unit mass.
I can apply weight = mass x gravitational field strength to new situations.Syllabus
Syllabus K223 / K224, 3(e). Apply weight = mass x gravitational field strength to new situations.
I can distinguish mass from weight.Syllabus
Syllabus K223 / K224, 3(f). Distinguish mass from weight.
In short
- Mass is the amount of matter in an object, in kg. It is the same everywhere.
- Weight is the gravitational force on the object, in N.
- W = mg, with g = 10 N/kg on Earth.
A force is a push or pull arising from an interaction between objects. To understand a force, identify what it acts on and what exerts it.
A string pulls on a trolley. A table pushes on a book. Earth attracts both objects. Each description names two interacting bodies, even when only one of them is moving.
Contact and non-contact forces
A contact force involves objects or materials touching. Its direction depends on the interaction.
- Normal contact force
- A surface pushes on an object in a direction perpendicular to the surface. A table supports a book in this way.
- Tension
- A stretched string or rope pulls on the object attached to it, along the string and away from the object.
- Friction
- Surfaces in contact exert a force that opposes their relative sliding, or their tendency to slide.
- Air resistance
- Air exerts a force on an object moving through it. Air is matter, so this is a contact interaction even though we cannot see the air.
Non-contact forces act without the objects touching. Gravitational attraction acts between masses; electrostatic forces act between electric charges; magnetic forces act between magnets or between a magnet and a suitable magnetic material. A magnet can attract a steel paper clip across a gap.
Forces are vectors, so give both magnitude and direction. For example, 6 N upwards describes a force of magnitude 6 newtons acting upwards. The quantity force may be written F or f; its unit is the newton, N.
Mass describes the object; weight is a force
- Mass
- A measure of the amount of matter in a body. Mass may be written m or M. It is a scalar, measured in kilograms (kg).
- Weight
- The gravitational force acting on a body. Weight is a vector, measured in newtons (N). Near Earth it acts downwards, towards Earth's centre.
A gravitational field is a region in which a mass experiences a force due to gravitational attraction. The gravitational field strength, g, is the gravitational force per unit mass at that point.
Near Earth's surface, g is approximately 10 N/kg: each kilogram experiences about 10 N of gravitational force. This corresponds to the approximately 10 m/s2 downward acceleration of free fall. Field strength is not 10 N/kg everywhere; use the value supplied in a question.
Worked example
The same object in two gravitational fields
An unchanged object has a mass of 1.5 kg. Find its weight where g = 10 N/kg, then where g = 1.6 N/kg.
- First location: W = 1.5 kg x 10 N/kg = 15 N.
- Second location: W = 1.5 kg x 1.6 N/kg = 2.4 N.
The kg units cancel against the kg in N/kg, leaving newtons. The mass remains 1.5 kg in both places. The weaker field produces a smaller weight; it does not remove matter from the object.
Measuring mass and weight
Use an electronic balance for a mass reading and a spring balance or newton-meter for a force reading. Choose a suitable range and check the zero. When measuring weight with a spring balance, hang the object freely and wait until it is stationary. The upward tension then has the same magnitude as the downward weight.
For example, an object gives a balance reading of 0.150 kg and a steady spring-balance reading of 1.5 N. These are different quantities. Their ratio gives g = 1.5 / 0.150 = 10 N/kg. Record the quantity and unit for each reading; do not call the force reading a mass.
For a small mass, the unit mg means milligram: 1 mg = 0.001 g = 0.000001 kg. In the equation W = mg, the letters instead mean the product m x g, mass multiplied by gravitational field strength. A unit after a mass reading and two quantities in an equation have different roles.
Convert grams to kilograms before using W = mg with g in N/kg. For example, 150 g = 0.150 kg. The prefix conversion changes the number and unit, not the amount of matter.
Check your understanding
An unchanged 0.60 kg object is moved to a place where g = 4.0 N/kg. Which statement is correct?
Show the answer
Its mass remains 0.60 kg and its weight is 2.4 N.
Use the supplied field strength: W = mg = 0.60 x 4.0 = 2.4 N. The gravitational force changes, but the amount of matter does not.
Try it step by step
Work it out in steps: Weight on Earth (g = 10 N/kg) in N, then Weight on the Moon (g = 1.6 N/kg) in N.
Show the answer
Problem 1.
Weight on Earth (g = 10 N/kg) in N: W = mg = 50 x 10 = 500 N
Weight on the Moon (g = 1.6 N/kg) in N: W = 50 x 1.6 = 80 N
Problem 2.
Weight on Earth (g = 10 N/kg) in N: W = 12 x 10 = 120 N
Weight on the Moon (g = 1.6 N/kg) in N: W = 12 x 1.6 = 19.2 N, which is 19 N to 2 sf
Problem 3.
Weight on Earth (g = 10 N/kg) in N: W = 70 x 10 = 700 N
Weight on the Moon (g = 1.6 N/kg) in N: W = 70 x 1.6 = 112 N (3 sf)
Practise an exam question
Write your answer first, then tick the mark points it makes.
Exam-style question
Define weight. An astronaut has a mass of 70 kg. State her mass on the Moon, where the gravitational field strength is 1.6 N/kg, and calculate her weight there. [2]
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