Lesson 1 of 3
Spectrum order and shared properties
I can state that electromagnetic waves are transverse and travel at the same speed in vacuum.Syllabus
Syllabus K223 / K224, 9(a). State that electromagnetic waves are transverse and travel at the same speed in vacuum.
I can order the main spectrum regions by wavelength and frequency.Syllabus
Syllabus K223 / K224, 9(b). Order the main spectrum regions by wavelength and frequency.
In short
- The order is radio, microwaves, infrared, visible light, ultraviolet, X-rays, gamma rays.
- Along that list the frequency goes up and the wavelength goes down.
- All of them travel at the same speed in a vacuum: 3.0 x 108 m/s.
- Speed = frequency x wavelength, so c = f x λ.
Make a guess. You are not marked.
A radio wave and an X-ray are sent across the same vacuum at the same moment. Which arrives first?
Show the answer
They arrive together, because both travel at the speed of light.
Every electromagnetic wave travels through a vacuum at the same speed, 3.0 x 108 m/s. The waves differ in frequency and wavelength, not in speed.
Radio waves, visible light and gamma rays are parts of one electromagnetic spectrum. They differ in wavelength and frequency, while sharing the same speed in vacuum.
Wavelength is a distance between equivalent adjacent points of a wave. Frequency is the number of complete cycles per second, in hertz. A wave transfers energy as it propagates.
What all electromagnetic waves share
All electromagnetic waves are transverse: their oscillations are perpendicular to the direction of propagation. The oscillating quantities are electric and magnetic fields, rather than air particles moving up and down.
They can travel through a vacuum, without a material medium. All travel at the same vacuum speed. For the calculations here, use the supplied value c = 3.0 x 108 m/s.
More detail (optional)
A sinusoidal drawing can represent how a field varies. It is not a wavy path followed by a photon or a row of air particles carrying the radiation.
Order wavelength and frequency in opposite directions
Read the same order in two directions
Moving down this list, frequency increases and wavelength decreases. All electromagnetic waves have the same speed in vacuum.
Visible light, enlarged
The separate region names are useful categories. Microwaves are also commonly described as part of the wider radio-frequency range.
Increasing frequency: radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, gamma rays.
Increasing wavelength: gamma rays, X-rays, ultraviolet, visible light, infrared, microwaves, radio waves.
Within visible light, red has a longer wavelength and lower frequency than violet. Both are electromagnetic waves. The named regions are convenient divisions of a continuous spectrum, not physical gaps; microwaves are also often included within the wider radio-frequency range.
Worked comparison
Two frequencies, one vacuum speed
A 100 MHz signal has f = 100 x 106 = 1.0 x 108 Hz. Its wavelength is λ = (3.0 x 108)/(1.0 x 108) = 3.0 m.
A 2.5 GHz signal has f = 2.5 x 109 Hz. Its wavelength is λ = (3.0 x 108)/(2.5 x 109) = 0.12 m.
The second signal repeats more often and has more closely spaced wave cycles. Both still travel at c in vacuum.
Try it step by step
Work it out in steps: Frequency in Hz, then Wavelength = c / f in m.
Show the answer
Problem 1.
Frequency in Hz: f = 150 x 1000000 = 150000000 Hz, which is 1.5 x 108 Hz
Wavelength = c / f in m: wavelength = 300000000 / 150000000 = 2.0 m (2 sf)
Problem 2.
Frequency in Hz: f = 600 x 1000000 = 600000000 Hz, which is 6.0 x 108 Hz
Wavelength = c / f in m: wavelength = 300000000 / 600000000 = 0.50 m (2 sf)
Problem 3.
Frequency in Hz: f = 2400 x 1000000 = 2400000000 Hz, which is 2.4 x 109 Hz
Wavelength = c / f in m: wavelength = 300000000 / 2400000000 = 0.125 m, which is 0.13 m to 2 sf
Work from wavelength when that is supplied
One nanometre is 10-9 m. For a supplied wavelength of 600 nm, λ = 6.00 x 10-7 m, so f = c/λ = 5.0 x 1014 Hz.
At 1200 nm, the wavelength is twice as large and the frequency is half as large: 2.5 x 1014 Hz. Wavelength and frequency cannot both increase while their product remains the same speed.
Radio reception ends with a different wave
A radio transmitter sends an electromagnetic signal to a receiver. The receiver processes the information and drives a loudspeaker. The loudspeaker then makes sound waves in the surrounding air.
The radio signal can cross a vacuum; the sound from the loudspeaker needs a material medium. In air, sound is longitudinal, while the radio wave is transverse.
Travel-time comparison
Equal paths through vacuum
Two electromagnetic signals are emitted together and each follows a 900 km vacuum path. Convert the distance to 900000 m.
t = distance/speed = 900000/(3.0 x 108) = 0.0030 s = 3.0 ms.
Both arrive together in this ideal comparison, regardless of their different frequencies.
Keep frequency separate from speed. More cycles per second does not mean faster propagation when the vacuum speed is fixed.
Check your understanding
A 100 MHz signal and a 2.5 GHz signal start together and follow equal 900 km paths through vacuum. Which comparison is correct?
Show the answer
They arrive together; the 2.5 GHz signal has the shorter wavelength.
Both travel at the same vacuum speed and take 900000/(3.0 x 108) = 0.0030 s. At fixed speed, wavelength equals speed divided by frequency: the wavelengths are 3.0 m and 0.12 m respectively.
Practise exam questions
Write your answer first, then tick the mark points it makes.
Exam-style question
State three properties shared by all electromagnetic waves. [3]
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Exam-style question
A radio station broadcasts at a frequency of 98.0 MHz. The speed of electromagnetic waves is 3.0 x 108 m/s. Calculate the wavelength of the radio waves. [3]
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