Lesson 3 of 9
Alkenes: a double bond creates new reactions
Distinguish substitution, addition and cracking.
O-Level 6092 (2026) / SEC G3 K324 (2027)
I can describe alkenes.Syllabus
Syllabus K324, 11.2(f). Describe alkenes
I can explain cracking.Syllabus
Syllabus K324, 11.2(h). Explain cracking
I can distinguish saturation.Syllabus
Syllabus K324, 11.2(i). Distinguish saturation
I can explain polyunsaturated food molecules.Syllabus
Syllabus K324, 11.2(k). Explain polyunsaturated food molecules
I can explain margarine manufacture.Syllabus
Syllabus K324, 11.2(l). Explain margarine manufacture
I can draw and name alkenes.Syllabus
Syllabus K324, 11.2(g). Draw and name alkenes
I can describe ethene reactions.Syllabus
Syllabus K324, 11.2(j). Describe ethene reactions
I can describe ethanol production.Syllabus
Syllabus K324, 11.3(d). Describe ethanol production
Alkenes: a double bond creates new reactions
Distinguish substitution, addition and cracking.
Make a guess. You are not marked.
Orange/brown bromine water is shaken with ethene, and separately with ethane, at room temperature. What do you see?
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Only the ethene decolourises it, by addition
Ethene has a C=C double bond, and bromine adds across it to make a colourless product. Ethane has only single bonds, so nothing adds.
Alkenes are unsaturated hydrocarbons containing a carbon-carbon double bond. For acyclic molecules with one C=C bond, their general formula is CnH2n. Ethene is CH2=CH2; propene is CH2=CH-CH3. Each carbon still has four bonds in total.
| Connectivity | Condensed structure |
|---|---|
| But-1-ene | CH2=CH-CH2-CH3 |
| But-2-ene | CH3-CH=CH-CH3 |
| Branched C4H8 | CH2=C(CH3)2 |
Worked exampleExpand an alkene without adding too many hydrogens
Draw propene from CH2=CH-CH3.
Try it first. Then show the worked stepsHide the worked steps
- Join three carbon atoms. Put the double bond between the first two; this uses two of each participating carbon's four bonds.
- Carbon 1 needs two C-H bonds. Carbon 2 already has three bonds in total to carbons, so needs only one H. Carbon 3 needs three H.
- Count the result: C3H6, with four bonds at each carbon.
Use the displayed propene below as a check. A double bond counts twice for valency but still connects the same two carbon atoms.
Displayed ethene
Complete displayed structure with 2 carbon, 4 hydrogen atoms: C2H4. Every bond and hydrogen is shown.
Displayed propene
Complete displayed structure with 3 carbon, 6 hydrogen atoms: C3H6. Every bond and hydrogen is shown.
Displayed but-1-ene
Complete displayed structure with 4 carbon, 8 hydrogen atoms: C4H8. Every bond and hydrogen is shown.
Displayed but-2-ene
Complete displayed structure with 4 carbon, 8 hydrogen atoms: C4H8. Every bond and hydrogen is shown.
Displayed branched C4 alkene
Complete displayed structure with 4 carbon, 8 hydrogen atoms: C4H8. Every bond and hydrogen is shown.
Aqueous bromine distinguishes an alkene from an alkane under the usual test conditions without UV. The alkene decolourises orange/brown bromine water because bromine adds across C=C. Ethene forms CH2Br-CH2Br. The alkane does not show this addition reaction. The colour change is an observation; unsaturation is the inference.
| Reagent or process | Essential conditions | Product/change |
|---|---|---|
| Oxygen: complete combustion | Ignition, sufficient oxygen | C2H4 + 3O2 -> 2CO2 + 2H2O |
| Aqueous bromine | Room conditions; no UV required | C2H4 + Br2 -> C2H4Br2 |
| Hydrogen | Nickel catalyst, heat | C2H4 + H2 -> C2H6 |
| Addition polymerisation | Suitable temperature, pressure and catalyst | Many ethene molecules form poly(ethene) |
Pure: steam adds across C=C with an acid catalyst such as phosphoric acid, at elevated temperature and pressure: C2H4(g) + H2O(g) -> C2H5OH(g). The ethanol is condensed after the reaction. Exact numerical temperatures and pressures are not required.
Cracking breaks larger hydrocarbons into smaller molecules using strong heating, often with a catalyst. Products can include smaller alkanes, alkenes and hydrogen. Examples of possible balanced changes are C10H22 -> C8H18 + C2H4, and C2H6 -> C2H4 + H2. Actual cracking produces a mixture; use atom conservation to deduce a missing product.
Polyunsaturated food molecules contain more than one C=C bond. Hydrogenating unsaturated vegetable oils with hydrogen and a nickel catalyst reduces the number of double bonds, making the product more solid and useful in margarine manufacture. This is addition, not polymerisation.
Check your understanding
C8H18 cracks to C6H14 and one other molecule. What is the other molecule?
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C2H4, ethene
Subtract: 8 - 6 = 2 carbons and 18 - 14 = 4 hydrogens remain, so C2H4. Check both totals.
Exam-style question
Describe a chemical test to distinguish between ethane and ethene. Give the result for each gas. [3]
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Check your understanding
Ethene reacts with hydrogen. Which line gives the condition and the product?
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Heated nickel catalyst; ethane
Hydrogen adds across the C=C bond: C2H4 + H2 -> C2H6. The same reaction hardens vegetable oils into margarine.
Check your understanding
A vegetable oil is polyunsaturated. How is it turned into a solid margarine?
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Hydrogen is added to some of its C=C bonds, using a heated nickel catalyst.
Polyunsaturated means many C=C bonds per molecule. With fewer double bonds the molecules pack more closely, so the melting point rises and the product is a soft solid.
Check your understanding
An unbranched alkene has 5 carbon atoms. What is its formula, and why is it unsaturated?
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C5H10; it has a C=C bond, so two fewer H than pentane
Alkenes follow CnH2n, so n = 5 gives C5H10. The double bond can open to add more atoms, which is what unsaturated means.