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K324 / 2027
Data and Experimental Skills

Lesson 4 of 8

Measurements and recording

Keep raw readings, temperature changes and observations interpretable.

O-Level 6092 (2026) / SEC G3 K324 (2027)

  • I can use apparatus and make detailed measurements and observations.Syllabus

    Syllabus K324, MMO. Use apparatus and make detailed measurements and observations

  • I can present data in an appropriate, useful form.Syllabus

    Syllabus K324, PDO. Present data in an appropriate, useful form

  • I can explain titration.Syllabus

    Syllabus K324, T1. Titration

  • I can measure reaction rates.Syllabus

    Syllabus K324, T2. Measure reaction rates

Record measurements that another person can interpret

Use the instrument scale, a clear table and observations that preserve the sequence.

Choose apparatus for the needed measurement: a volumetric pipette delivers a fixed accurate volume, a burette delivers a variable accurately measured volume, a measuring cylinder is suitable for less exact volume work, and a balance measures mass. Read the scale at eye level to avoid parallax; use the bottom of the meniscus for a clear aqueous solution unless the instructions specify otherwise.

A result table keeps raw readings visible
TrialInitial burette / cm3Final burette / cm3Titre / cm3
Rough0.0024.8024.80
11.1025.5024.40
20.2024.6524.45
30.3024.7024.40

For Secondary Chemistry, the syllabus normally expects burette readings to the nearest 0.05 cm3, and sufficient titrations to obtain, for a good end-point, two titres within 0.20 cm3. Record both readings and the difference. Follow the question if it gives a particular agreement criterion; do not include the rough titre in a precise mean.

Worked exampleSelect a justified mean titre

Use the precise titrations in the table; their maximum separation is 0.05 cm3.

Try it first. Then show the worked stepsHide the worked steps
  1. Trials 1, 2 and 3 form a close group. The rough trial was for locating the end-point.
  2. Mean = (24.40 + 24.45 + 24.40) / 3 = 24.4166... cm3.
  3. Record a suitable rounded mean of 24.42 cm3; retain the unrounded value through subsequent calculations where useful.
Answer

24.42 cm3, with the selected trials clearly identified.

Separate raw observations from interpretation. "A white precipitate forms after three drops and dissolves in excess" preserves information that "positive test" loses. Record colour, physical state, changes on standing or warming, and any confirmed gas test. Put units in table headings; do not attach a unit to a pure ratio.

Check your understanding

The initial burette reading is 2.35 cm3 and the final reading is 26.70 cm3. What volume was delivered?

  1. 24.35 cm3
  2. 26.70 cm3
  3. 29.05 cm3
Show the answer

24.35 cm3

Delivered volume = final - initial = 26.70 - 2.35 = 24.35 cm3.

Measure temperature changes and changes in mass

Distinguish a reading from the chemical quantity it represents.

For a temperature-change experiment, measure a stable starting temperature, combine the stated quantities, stir consistently and follow temperature with time. Use a suitable thermometer or probe, keeping it immersed appropriately without resting on the vessel. A lid and insulation reduce exchange with the surroundings. Do not treat a single late reading as the maximum change if the mixture has already cooled.

A temperature rise indicates energy transferred to the measured surroundings in an exothermic process; a fall indicates an endothermic process under comparable conditions. To compare reactions fairly, account for the amounts reacting and the mass being warmed, rather than ranking enthalpy changes by temperature rise alone.

Check your understanding

Two reactions give the same temperature rise but warm different masses of solution. Did they release the same energy?

  1. Not necessarily. Energy depends on the type of cup, not the mass of the solution.
  2. Yes. The same temperature rise means the same energy was given out.
  3. Not necessarily. Energy depends on the mass warmed as well as the rise.
Show the answer

Not necessarily. Energy depends on the mass warmed as well as the rise.

Q = mc(delta T). The same rise in a larger mass of solution means more energy was released. Compare the masses and amounts before concluding.