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K324 / 2027
Acid-Base Chemistry

Full chapter

Acid-Base Chemistry

Use ions and reaction patterns to explain acids, bases and salts.

O-Level 6092 (2026) / SEC G3 K324 (2027)

01

Acids, alkalis and pH

Read acidity as an ion balance, not just a colour.

Make a guess. You are not marked.

Hydrochloric acid of pH 1 is diluted ten times with water. What is the pH now?

  1. Exactly pH 7, because water is neutral
  2. Still pH 1, as the acid is the same
  3. Higher than 1 but still below 7
Show the answer

Higher than 1 but still below 7

There are fewer hydrogen ions in each cm3, so the solution is less acidic. Adding water never makes an acid neutral or alkaline.

An acid produces H+ ions in aqueous solution. An alkali is a soluble base that produces OH- ions in water. A base neutralises an acid; insoluble copper(II) oxide is a base but is not an alkali. Acidic and alkaline solutions both contain H+ and OH-; their relative concentrations differ.

Universal Indicator and the pH scale
Solution at room temperatureRelative ionspH and typical indicator colour
AcidicMore H+ than OH-Below 7; red through orange/yellow as pH increases
NeutralEqual H+ and OH-7; green
AlkalineMore OH- than H+Above 7; blue through purple

Compare colours with the supplied indicator chart. Universal Indicator estimates a pH range; a suitable calibrated pH probe gives a numerical reading. We use qualitative comparisons here, not calculations of pH from hydrogen-ion concentration.

Soil pH affects nutrient availability and plant growth. Calcium hydroxide can treat excessively acidic soil because it neutralises acid. Adding too much creates a different problem: overly alkaline soil. Determine the starting pH and add an appropriate amount rather than assuming more is better.

Check your understanding

Does a neutral solution contain no H+ ions?

  1. It has no H+ ions, because H+ ions are what make a solution acidic.
  2. It has H+ ions, balanced by an equal concentration of OH- ions.
  3. It has H+ ions if a little acid was added to it beforehand, and none otherwise.
Show the answer

It has H+ ions, balanced by an equal concentration of OH- ions.

Water itself ionises slightly, so any aqueous solution has some H+ and OH-. Neutral means the two concentrations are equal, not that the ions are absent.

02

Recognise the reaction pattern

Predict the salt and the other products.

Acid and base reactions
ReactantsProductsBalanced example
Acid + suitable metalSalt + hydrogenMg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)
Acid + baseSalt + waterCuO(s) + H2SO4(aq) -> CuSO4(aq) + H2O(l)
Acid + carbonateSalt + water + carbon dioxideCaCO3(s) + 2HCl(aq) -> CaCl2(aq) + H2O(l) + CO2(g)
Alkali + ammonium salt, warmSalt + water + ammoniaNH4Cl(aq) + NaOH(aq) -> NaCl(aq) + H2O(l) + NH3(g)

The acid supplies the salt anion: hydrochloric acid gives chlorides, sulfuric acid sulfates, and nitric acid nitrates. The metal or base supplies the cation. Not every metal reacts with dilute acid: copper, for example, does not release hydrogen from dilute hydrochloric acid.

For an acid reacting with an alkali, the reacting ions are H+(aq) + OH-(aq) -> H2O(l). This is neutralisation. The other dissolved ions are spectators. For an ammonium salt and alkali, NH4+(aq) + OH-(aq) -> NH3(g) + H2O(l); warming helps ammonia escape.

Worked examplePredict and confirm the gas

Dilute acid is added to a carbonate and bubbles appear. How should the result be described?

Try it first. Then show the worked stepsHide the worked steps
  1. Predict carbon dioxide from the carbonate reaction pattern.
  2. Report effervescence as the observation.
  3. Pass the gas into limewater: a white precipitate supports carbon dioxide.
Answer

Effervescence alone does not identify a gas. Carbon dioxide turns limewater milky; hydrogen instead gives a pop with a lighted splint.

Check your understanding

What salt forms when zinc reacts with dilute sulfuric acid?

  1. Zinc sulfite, ZnSO3, with oxygen gas given off
  2. Zinc sulfide, ZnS, with water as the other product
  3. Zinc sulfate, ZnSO4, with hydrogen gas given off
Show the answer

Zinc sulfate, ZnSO4, with hydrogen gas given off

Metal + acid -> salt + hydrogen. The salt takes its first name from the metal and its second from the acid: Zn(s) + H2SO4(aq) -> ZnSO4(aq) + H2(g).

03

Classify an oxide by its reactions

Metal/non-metal character suggests a pattern, but exceptions matter.

Four oxide classes
ClassBehaviourExamples
BasicReacts with acids to form salt and waterCuO, MgO: generally metal oxides
AcidicReacts with bases to form salt and waterCO2, SO2: generally non-metal oxides
AmphotericReacts with both acids and strong alkalisAl2O3, ZnO
NeutralDoes not show typical acidic or basic oxide reactionsCO, NO; being a non-metal oxide does not guarantee acidity

For example, CO2(g) + 2NaOH(aq) -> Na2CO3(aq) + H2O(l) with excess alkali shows acidic-oxide behaviour. CuO reacting with an acid shows basic behaviour. An insoluble oxide can still be acidic or basic: classification is not determined by whether it dissolves in water.

Check your understanding

An oxide reacts with hydrochloric acid and also with aqueous sodium hydroxide. How is it classified?

  1. Amphoteric, as it reacts with acids and bases
  2. Neutral, because its acidic and basic sides cancel out
  3. Basic, because it reacts with hydrochloric acid
Show the answer

Amphoteric, as it reacts with acids and bases

A basic oxide reacts with acids only, and an acidic oxide with bases only. Reacting with both is the evidence for an amphoteric oxide, such as zinc oxide or aluminium oxide.

Sort these

Sort the oxides by how they behave with acids and alkalis.

Show the answer

Acidic: SO2 / CO2

Basic: CaO / CuO

Amphoteric: ZnO / Al2O3

Neutral: NO / CO

04Pure only

Strong and weak is different from concentrated and dilute

Separate extent of ionisation from amount per unit volume.

Make a guess. You are not marked.

Equal pieces of magnesium are dropped into hydrochloric acid and into ethanoic acid. Both acids have the same concentration. Which fizzes faster?

  1. The hydrochloric acid, as it has more H+ ions
  2. Both fizz at the same rate, as the concentrations match
  3. The ethanoic acid, as it is an organic acid
Show the answer

The hydrochloric acid, as it has more H+ ions

Hydrochloric acid is a strong acid and ionises completely, so it has a higher concentration of hydrogen ions to collide with the magnesium.

A strong acid ionises essentially completely in water: HCl(aq) -> H+(aq) + Cl-(aq). A weak acid ionises only partly: CH3COOH(aq) reversibly forms H+(aq) and CH3COO-(aq). Many acid molecules remain un-ionised.

Concentration describes the amount of acid per unit volume, whether or not its molecules ionise. A strong acid can be dilute, and a weak acid can be concentrated. At the same concentration, comparing suitable monoprotic acids under the same conditions, the stronger acid produces more H+, usually gives a lower pH and reacts faster initially with magnesium.

Check your understanding

Does diluting hydrochloric acid turn it into a weak acid?

  1. Yes. A dilute acid has fewer H+ ions per dm3, and that is what makes an acid weak.
  2. No. It is less concentrated, but it still ionises fully, so it stays strong.
  3. No. Diluting it makes it a stronger acid, because each molecule has more water to ionise in.
Show the answer

No. It is less concentrated, but it still ionises fully, so it stays strong.

Strength is about how fully an acid ionises in water. Concentration is about how much acid is in each dm3. Diluting changes the concentration, not the strength.

05Pure only

Use solubility rules to choose starting materials

An insoluble product can be separated as a precipitate.

General salt-solubility rules
FamilyRule and important exceptions
Group 1 and ammonium saltsSoluble
NitratesSoluble
ChloridesGenerally soluble; silver chloride and lead(II) chloride are exceptions
SulfatesGenerally soluble; barium sulfate and lead(II) sulfate are insoluble; calcium sulfate is sparingly soluble
CarbonatesGenerally insoluble except Group 1 and ammonium carbonates
HydroxidesGenerally insoluble except Group 1 hydroxides; calcium hydroxide is slightly soluble

Precipitation occurs when dissolved ions meet and form an insoluble solid. Mixing Ba(NO3)2(aq) and Na2SO4(aq) gives BaSO4(s). The ionic equation is Ba2+(aq) + SO42-(aq) -> BaSO4(s). Choose soluble starting salts so both required ions are available to mix.

Check your understanding

Why mix barium nitrate solution with sodium sulfate solution, rather than mixing the two dry solids?

  1. Water reacts with sodium sulfate to make the sulfate ions needed for the precipitate.
  2. In solution the Ba2+ and SO42- ions can move and meet to form barium sulfate.
  3. The dry solids would react too violently, so water is added to slow the reaction.
Show the answer

In solution the Ba2+ and SO42- ions can move and meet to form barium sulfate.

In the dry solids the ions are fixed in their lattices. Dissolving frees them, so Ba2+ and SO42- collide and insoluble BaSO4 precipitates.

06Pure only

Prepare and purify the salt you want

The method follows the solubility of both product and reactants.

Choose the route
  1. Insoluble salt

    Mix two suitable soluble salts. Filter the precipitate, wash with distilled water, then dry.

  2. Soluble salt with an insoluble reactant

    React dilute acid with excess suitable metal, insoluble base or insoluble carbonate. Filter away excess solid, concentrate the filtrate, cool to crystallise, filter and dry.

  3. Soluble salt from acid and alkali

    Use titration to find exact reacting volumes. Repeat those volumes without indicator, then concentrate and crystallise.

Worked examplePrepare copper(II) sulfate crystals

Choose reagents and explain the key steps.

Try it first. Then show the worked stepsHide the worked steps
  1. Warm dilute sulfuric acid gently and add copper(II) oxide in small portions with stirring until some remains unreacted.
  2. Excess solid ensures the acid is used up. Filter away the unreacted oxide.
  3. Gently evaporate some water from the filtrate, then allow it to cool and crystallise.
  4. Filter crystals, wash with a little cold distilled water and dry between filter papers.
Answer

CuO(s) + H2SO4(aq) -> CuSO4(aq) + H2O(l). Copper metal is unsuitable with dilute sulfuric acid because it does not release hydrogen.

A suitable metal such as magnesium can prepare a soluble salt with dilute acid, but extremely reactive metals such as sodium are unsuitable. An insoluble carbonate such as zinc carbonate is another route; effervescence helps track acid consumption. For sodium chloride, both hydrochloric acid and sodium hydroxide remain dissolved, so excess cannot be removed by filtration: titration is needed.

Worked exampleMake a soluble salt when both reactants are solutions

Prepare pure potassium chloride crystals from dilute hydrochloric acid and potassium hydroxide solution. Why is titration needed?

Try it first. Then show the worked stepsHide the worked steps
  1. Use a pipette to put a known fixed volume of KOH(aq) in a conical flask. Add a few drops of a suitable indicator such as methyl orange.
  2. Add HCl(aq) from a burette while swirling, dropwise near the endpoint. Record initial and final readings to find the volume giving the indicator colour change. Repeat to obtain consistent volumes.
  3. Mix the same measured neutralising volumes in clean apparatus without indicator. KOH(aq) + HCl(aq) -> KCl(aq) + H2O(l).
  4. Gently evaporate some water, cool to crystallise, then filter the crystals, wash with a little cold distilled water and dry.
Answer

Titration avoids soluble excess acid or alkali, which filtration cannot remove. The indicator-free repeat prevents indicator contaminating the salt.

Check your understanding

When preparing a pure salt by titration, why repeat the mixing with the measured volumes but no indicator?

  1. So more salt forms, because the indicator uses up part of the acid in the flask.
  2. To check the end-point again, because the first titration result might be wrong.
  3. So the indicator does not stay in the salt as an impurity when it crystallises.
Show the answer

So the indicator does not stay in the salt as an impurity when it crystallises.

The first titration finds the exact volumes that neutralise. Repeating with the same volumes and no indicator gives a solution of the salt alone. Adding extra alkali would leave a soluble impurity.

Exam-style question

Describe how you would prepare pure, dry crystals of sodium sulfate from dilute sulfuric acid and aqueous sodium hydroxide. [4]

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Put these in order

Put the steps for making copper(II) sulfate crystals from copper(II) oxide in order.

Show the answer

1. Warm some dilute sulfuric acid in a beaker Warm acid reacts faster with the oxide that is added next.

2. Add copper(II) oxide a little at a time, stirring, until some stays undissolved Undissolved solid shows all the acid has been used, so the excess must now be removed.

3. Filter to remove the excess copper(II) oxide The filtrate is copper(II) sulfate solution, which must be concentrated.

4. Heat the filtrate until it is saturated A saturated solution forms crystals as it cools.

5. Leave to cool, then filter, rinse with a little cold water and dry the crystals

07Pure only

Ammonia: choose useful industrial conditions

Reversible reactions require a balance between yield, speed and cost.

Make a guess. You are not marked.

In the Haber process, N2(g) + 3H2(g) <=> 2NH3(g). What does raising the pressure do to the yield of ammonia?

  1. The yield increases, as fewer gas moles form
  2. The yield decreases, as the gases are squeezed
  3. Pressure changes the rate but not the yield
Show the answer

The yield increases, as fewer gas moles form

The right side has 2 moles of gas and the left side has 4. Higher pressure favours the side with fewer gas molecules, which is ammonia.

In the Haber process, nitrogen from air reacts with hydrogen to form ammonia: N2(g) + 3H2(g) reversibly forms 2NH3(g). The syllabus connects hydrogen supply to cracking crude-oil hydrocarbons. The reverse reaction breaks ammonia down, so conversion is not necessarily complete.

Industrial plants use elevated pressure, a moderately high temperature and an iron catalyst. Ammonia is cooled and removed; unreacted nitrogen and hydrogen are recycled. A catalyst speeds attainment of the final composition without improving the equilibrium yield. This chapter uses supplied trends, not Le Chatelier's principle.

Illustrative process data at fixed pressure
TemperatureAmmonia yieldTime to approach final composition
LowerHigherLong
IntermediateIntermediatePractical
HigherLowerShort

Worked exampleInterpret a compromise

Given these trends, why might a manufacturer avoid the lowest temperature?

Try it first. Then show the worked stepsHide the worked steps
  1. A high eventual yield is not useful if formation is too slow.
  2. An intermediate temperature can give more ammonia per hour despite a lower final percentage.
  3. Higher pressure may improve yield in supplied data but adds compression costs and demands stronger equipment.
Answer

Use yield, production rate and cost together. Do not infer that the highest yield automatically gives the most economical operating conditions.

Check your understanding

In the Haber process, why are the gases left after ammonia is removed recycled?

  1. They are ammonia that failed to condense, which is cooled again to collect it.
  2. They are unreacted nitrogen and hydrogen, which get another chance to react.
  3. They are waste gases from the iron catalyst, which are cleaned before release.
Show the answer

They are unreacted nitrogen and hydrogen, which get another chance to react.

The reaction is reversible, so each pass converts only part of the gases. Recycling them raises the overall conversion and wastes less raw material.

Quick revision

Revisit the essentials, then return to an explanation when you need it.

Exam definitions: learn these in mark-scheme words
TermDefinition to write
AcidA substance that produces hydrogen ions, H+(aq), when dissolved in water.
AlkaliA soluble base that produces hydroxide ions, OH-(aq), when dissolved in water.
BaseA substance that reacts with an acid to form a salt and water only. Most bases are metal oxides or hydroxides.
NeutralisationThe reaction between hydrogen ions and hydroxide ions to form water: H+(aq) + OH-(aq) → H2O(l).
SaltThe compound formed when the hydrogen ions of an acid are replaced by metal ions or ammonium ions.
Pure only
Pure only: more exam definitions
TermDefinition to write
Strong acidAn acid that ionises (dissociates) completely in water.
Weak acidAn acid that ionises (dissociates) only partially in water.

Acids supply H+; alkalis supply OH-. Acid + base gives salt and water; carbonate also gives CO2; suitable metal gives H2. Alkali and ammonium salt release NH3 on warming.

Pure only

Pure: select salt preparation from solubility, separate acid strength from concentration, and interpret Haber conditions using supplied yield/rate/cost evidence.

Scope

Learning outcomes

5. Acid-Base Chemistry (6092 / K324). Use the outcome map to find the explanation for a particular syllabus requirement.

See the learning outcome map
  1. 5.1(a) Define acids and alkalis

    • Aqueous H+ and OH-
    • Universal Indicator

    Acids, alkalis and pH

  2. 5.1(b) Compare acidity and alkalinity

    • Relative ion concentrations
    • Indicator colours
    • pH scale, no logarithmic calculation

    Acids, alkalis and pH

  3. 5.1(c) Distinguish strong and weak acids

    • Extent of ionisation
    • Distinguish concentration

    Strong and weak is different from concentrated and dilute

  4. 5.1(d) Describe acid reaction patterns

    • Metals, bases and carbonates
    • Salt products

    Recognise the reaction pattern

  5. 5.1(e) Explain neutralisation

    • H+ + OH- -> water

    Recognise the reaction pattern

  6. 5.1(f) Explain control of soil acidity

    • Importance of soil pH
    • Calcium hydroxide treatment

    Acids, alkalis and pH

  7. 5.1(g) Describe base reactions

    • With acids
    • With ammonium salts on warming

    Recognise the reaction pattern

  8. 5.1(h) Classify oxides

    • Acidic, basic, amphoteric, neutral
    • Metal/non-metal character and exceptions

    Classify an oxide by its reactions

  9. 5.2(a) Prepare, separate and purify salts

    • Precipitation
    • Titration
    • Acids with metals, insoluble bases and insoluble carbonates

    Prepare and purify the salt you want

  10. 5.2(b) Apply salt-solubility rules

    • Nitrates
    • Chlorides including silver and lead
    • Sulfates including barium, calcium and lead
    • Carbonates and hydroxides
    • Group 1 and ammonium salts

    Use solubility rules to choose starting materials

  11. 5.2(c) Select a salt-preparation route

    • Suitable starting materials
    • Product and reactant solubility

    Use solubility rules to choose starting materialsPrepare and purify the salt you want

  12. 5.3(a) Identify ammonia feedstocks

    • Nitrogen from air
    • Hydrogen from cracking crude-oil hydrocarbons

    Ammonia: choose useful industrial conditions

  13. 5.3(b) Recognize reversibility

    • Ammonia synthesis and decomposition

    Ammonia: choose useful industrial conditions

  14. 5.3(c) Interpret industrial process data

    • Haber temperature, pressure, rate/yield/cost
    • No Le Chatelier requirement

    Ammonia: choose useful industrial conditions