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K223 / K225 / 2027
Data and Experimental Skills

Lesson 5 of 7

Titration and quantitative analysis

Make the measured volume correspond to the reacting amount.

SEC G2 Science K223 / K225 (2027)

  • I can select and use techniques, apparatus and materials.Syllabus

    Syllabus K223 / K225, C1. Select and use techniques, apparatus and materials

Make a titre correspond to the reacting amounts

The endpoint, rinsing and complete transfer determine what the number means.

A careful acid-base titration
  1. Prepare the measured solutions

    Rinse the burette with its solution and the pipette with the solution it will measure. Fill the burette tip, remove the funnel and record the initial reading. Use a pipette filler.

  2. Transfer a fixed aliquot

    Deliver the pipetted solution into a clean conical flask. Allow the pipette to drain as designed; do not blow out a residual tip drop unless it is a blow-out pipette.

  3. Locate the endpoint

    Add a small consistent amount of a suitable indicator. Swirl during addition, use a white background and add titrant dropwise near the endpoint. Rinse flask walls with distilled water if needed.

  4. Repeat and calculate

    Record the final reading and titre. Obtain agreeing precise titres, select a justified mean, then use concentration, volume and the balanced mole ratio.

The equivalence point is the stoichiometric completion of reaction. The endpoint is the observed indicator change. Choose an indicator whose transition lies in the steep pH change near equivalence; universal indicator gives a broad colour change and is unsuitable for precise titration. The required final colour depends on the indicator and which solution is added.

Check your understanding

After pipetting the alkali into the conical flask, a student adds a little distilled water. How does this affect the titre?

  1. No effect, because the amount of alkali in the flask is unchanged.
  2. The titre falls, because the alkali is now more dilute.
  3. The titre rises, because extra water must also be neutralised.
Show the answer

No effect, because the amount of alkali in the flask is unchanged.

Water dilutes the alkali but does not change the moles present, so the same volume of acid neutralises it. This assumes nothing is lost and the end-point is still clear.