Lesson 3 of 3
The mole is a counting unit
Connect microscopic particles to measurable mass.
SEC G2 Science K223 / K225 (2027)
I can define relative atomic mass.Syllabus
Syllabus K223 / K225, 4.2(a). Define relative atomic mass
I can define and calculate relative molecular/formula mass.Syllabus
Syllabus K223 / K225, 4.2(b). Define and calculate relative molecular/formula mass
I can calculate amount, mass and molar mass.Syllabus
Syllabus K223 / K225, 4.2(c). Calculate amount, mass and molar mass
The mole is a counting unit
Connect microscopic particles to measurable mass.
Make a guess. You are not marked.
You weigh out 12 g of carbon and 12 g of magnesium. Use C = 12 and Mg = 24. Which sample contains more atoms?
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The 12 g of carbon, as its atoms are lighter
Carbon atoms are half as heavy, so 12 g holds 1 mol of carbon atoms but only 0.5 mol of magnesium atoms.
Relative atomic mass, Ar, compares the average mass of an atom with one twelfth of the mass of a carbon-12 atom. Relative molecular mass, Mr, makes the same comparison for a molecule. Add the Ar values in its formula. For an ionic compound, call this relative formula mass instead. These relative masses have no units.
A mole is a fixed number of particles, so chemists can count particles by weighing them. The mass of one mole of a substance is its molar mass, M, in g mol-1. It has the same number as the relative atomic, molecular or formula mass: Ar(C) = 12, so one mole of carbon atoms has a mass of 12 g; Mr(H2O) = 18, so one mole of water molecules has a mass of 18 g. Always say which particles you are counting: atoms, molecules or formula units.
- Find the amount
n = m / M. Mass in g divided by molar mass in g mol-1 gives moles.
- Find the mass
m = n x M. Moles multiplied by molar mass gives grams.
- Find the molar mass
M = m / n. Compare the answer with Mr values to suggest what the substance is.
Worked exampleAccount for brackets in a formula
Find the relative formula mass of Ca(OH)2 and the amount in 3.70 g. Use Ca = 40, O = 16, H = 1.
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- Mr = 40 + 2(16 + 1) = 74.
- Molar mass = 74 g mol-1.
- n = 3.70/74 = 0.0500 mol.
0.0500 mol of Ca(OH)2 formula units; if fully dissolved, this produces 0.100 mol of OH- ions.
Try it step by step
Work it out in steps: Molar mass, then Amount in moles.
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Problem 1.
Molar mass: M(Na2CO3) = 2(23) + 12 + 3(16) = 106 g mol-1. Count every atom in the formula: two Na, one C and three O.
Amount in moles: n = m / M = 5.30 / 106 = 0.0500 mol of Na2CO3 formula units.
Problem 2.
Molar mass: M(MgSO4) = 24 + 32 + 4(16) = 120 g mol-1.
Amount in moles: n = m / M = 6.00 / 120 = 0.0500 mol. Write 0.0500, not 0.05, to show 3 significant figures.
Problem 3.
Molar mass: M(Ca(NO3)2) = 40 + 2(14 + 3 x 16) = 40 + 2(62) = 164 g mol-1. The 2 outside the bracket doubles everything inside it.
Amount in moles: n = m / M = 4.10 / 164 = 0.0250 mol of Ca(NO3)2.
Worked exampleFrom moles to mass
What is the mass of 0.25 mol of carbon dioxide, CO2? Use C = 12, O = 16.
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- Mr(CO2) = 12 + 2(16) = 44, so M = 44 g mol-1.
- m = n x M = 0.25 x 44 = 11 g.
11 g. Check the size: a quarter of a mole should have a quarter of the mass of one mole, and 44 / 4 = 11.
Check your understanding
How many moles of oxygen atoms are in 0.25 mol of O2 molecules?
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0.50 mol of oxygen atoms, since each molecule has two
Each O2 molecule holds two O atoms, so 0.25 x 2 = 0.50 mol of atoms. The amount of molecules is still 0.25 mol; always say which particle you are counting.
Worked exampleIdentify a substance from its molar mass
A 9.0 g sample of a pure substance contains 0.50 mol. Is it water (Mr = 18) or glucose (Mr = 180)?
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- M = m / n = 9.0 / 0.50 = 18 g mol-1.
- Compare with the Mr values: 18 matches water, not glucose.
Water. The units check too: grams divided by moles gives g mol-1.
Check your understanding
How many moles of sodium hydroxide, NaOH, are in 4.0 g? Use Na = 23, O = 16, H = 1.
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0.10 mol, since Mr = 40 and 4.0 / 40 = 0.10
Mr = 23 + 16 + 1 = 40, so the molar mass is 40 g mol-1. Moles = mass / molar mass = 4.0 / 40 = 0.10 mol.