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8873 / 2027
The Periodic Table

Lesson 1 of 3

Atomic and physical trends

Change the explanation when the structure changes.

A-Level 8873, revised syllabus (2026-2027)

  • I can recognise electronic patterns.Syllabus

    Syllabus 8873, 4(a). Recognise electronic patterns.

  • I can explain radius, first-ionisation and electronegativity trends.Syllabus

    Syllabus 8873, 4(b). Explain radius, first-ionisation and electronegativity trends.

  • I can explain melting and conductivity across Period 3.Syllabus

    Syllabus 8873, 4(c). Explain melting and conductivity across Period 3.

  • I can explain halogen volatility.Syllabus

    Syllabus 8873, 4(d). Explain halogen volatility.

Read the electron pattern across and down

A period adds electrons to one main shell; a group repeats an outer pattern.

Period 3: the outer shell fills
ElementOuter configurationGroup
Na3s11
Mg3s22
Al3s2 3p113
Si3s2 3p214
P3s2 3p315
S3s2 3p416
Cl3s2 3p517

From Na to Cl the nuclear charge increases. Added electrons enter the third shell, so the shielding of these outer electrons changes relatively little. Stronger effective attraction generally draws the outer shell closer: atomic radius decreases, while first ionisation energy and electronegativity generally increase.

Explain the two first-ionisation-energy exceptions using orbitals. Al loses a higher-energy 3p electron rather than Mg's 3s electron. S loses a paired 3p electron, with extra electron-electron repulsion, whereas P has three singly occupied 3p orbitals. The resulting dips do not mean the general nuclear-charge trend is wrong.

Group 17: same outer pattern, a different shell
ElementOuter configurationRelative pattern down the group
Cl3s2 3p5Smaller atom; stronger attraction to outer electrons
Br4s2 4p5An additional principal shell
I5s2 5p5Larger atom; more shielding

Down Cl to I, the outer shell is farther from the nucleus and is more shielded. These effects outweigh the increased nuclear charge: atomic radius increases, first ionisation energy decreases and electronegativity decreases. The number of outer electrons stays seven.

For ionic radii, compare species with similar electron arrangements. Na+, Mg2+ and Al3+ each have ten electrons: increasing nuclear charge contracts this isoelectronic series. P3-, S2- and Cl- each have eighteen; their radii also decrease in that order. Crossing from a cation series to an anion series introduces a large jump, so ionic radius does not form one smooth decreasing line across Period 3. Down Cl-, Br-, I-, more occupied shells give larger ions.

Check your understanding

Put Na+, Mg2+ and Al3+ in order of decreasing radius.

  1. Al3+ > Mg2+ > Na+, because more protons means a bigger nucleus and ion
  2. Na+ > Mg2+ > Al3+, because nuclear charge rises with the same 10 electrons
  3. The three are the same size, because they have the same 10 electrons
Show the answer

Na+ > Mg2+ > Al3+, because nuclear charge rises with the same 10 electrons

All three ions have 10 electrons, but 11, 12 and 13 protons. A larger nuclear charge pulls the same electrons in more strongly.

A melting-point trend can change its cause

First classify the structure; then compare the attractions.

Why Period 3 melting points do not form a smooth trend
ElementsStructureExplanation
Na, Mg, AlMetallicMelting requires overcoming metallic attraction. More delocalised electrons and greater positive-ion charge help explain the increase from Na to Mg/Al.
SiGiant covalentMany strong covalent bonds extend through the solid, so its melting point is high.
P, S, ClSimple molecular: P4, S8, Cl2Intermolecular attractions, not the bonds inside the molecules, are overcome. These melt far below silicon.

The molecular comparison uses white phosphorus, P4. S8 has a larger, more easily polarised electron cloud than P4, so sulfur has stronger intermolecular attractions and a higher melting point. Cl2 is much smaller and melts much lower. Other allotropes can have different structures; an element name alone does not specify an allotrope.

Na, Mg and Al conduct electricity through mobile delocalised electrons. Conductivity generally increases from Na to Al: each atom supplies one, two and three valence electrons respectively, giving a greater density of mobile charge carriers. The ions remain in the solid lattice. Silicon's covalent network has far fewer mobile carriers at room temperature, so it is a semiconductor with much lower conductivity than the metals. P4, S8 and Cl2 lack mobile charged particles and are electrical insulators in their pure forms.

Halogen volatility: Cl2 to I2
HalogenAppearance near room conditionsVolatility
ChlorineGreenish-yellow gasHighest of these three
BromineRed-brown liquidIntermediate
IodineDark solid; purple vapour on heatingLowest of these three

Down the group, the molecules have more electrons and more polarisable electron clouds. Instantaneous dipole-induced dipole attractions become stronger, so more energy is needed to separate molecules and volatility decreases. This is an intermolecular explanation; do not use the X-X covalent bond strength to explain boiling.

Check your understanding

Sulfur atoms have more protons than silicon atoms. Why does sulfur melt at a much lower temperature?

  1. Silicon is a giant covalent network; sulfur is made of S8 molecules held by weak forces.
  2. Sulfur is a metal with weak metallic bonds, while silicon is a non-metal with ionic bonds.
  3. Sulfur's extra protons pull its electrons in, so its bonds become weaker and easier to break.
Show the answer

Silicon is a giant covalent network; sulfur is made of S8 molecules held by weak forces.

Melting silicon breaks strong covalent bonds throughout the network. Melting sulfur overcomes only weak forces between S8 molecules. The structure matters, not the proton count.